Question

What is an equation of the line that passes through the points (-6, -3) and
(-3, -5)?

Answer 1

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Hey buddy ....

I really appreciate God to give me this chance to help u.

Let's see what to do...

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First we need to find the slope of the line using this equation :

Suppose a = ( - 6 , - 3 ) , b = ( - 3 , - 5 )

`slope = m = (y(b) - y(a))/(x(b) - x(a)) \\`

Just need to put the coordinates in the equation:

`slope = ( - 5 - ( - 3))/( - 3 - ( - 6)) \\`

`slope = ( - 5 + 3)/( - 3 + 6) \\`

`slope = ( - 2)/( - 3) \\`

`slope = (3)/(2) \\`

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We have this equation as the point-slope form of the linear functions :

`y - y(one \: \: of \: \: the \: \: given \: \: points) = (slope) * ( \: x - x(o \: o \: f \: t \: g \: p) \: ) \\`

Now just need to put the slope and one the given points ( a or b ) in the above equation:

I like to use a ( you can use b bro )

`y - ( - 3) = (3)/(2) * (x - ( - 6) \: ) \\`

`y + 3 = (3)/(2) * (x + 6) \\`

`y + 3 = (3)/(2) x + 9 \\`

Subtract sides 3

`y + 3 - 3 = (3)/(2) x + 9 - 3 \\`

`y = (3)/(2) x + 6 \\`

And this is the equation of the line.

So we're done.....

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Take care dude ❤❤❤❤❤

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Answer 2

y = − 2 /3 x − 7

Explanation:

Use the slope formula and slope-intercept form y = m x + b to find the equation.