Given: Initial velocity of train (u) = 0
Acceleration of train (a) = 1.5 m/s²
Travel time (t) = 5.0 s
To Find: The distance traveled by train in the given time interval
Formula Used: 2nd kinematic equation of motion
s = ut + (1/2) at²
Here, all alphabets are in their usual meanings.
Now, using equation (i), we shall calculate the value of s
s = 0×5.0 + (1/2) ×1.5×(5.0)² m
or, s = 18.75 m
Hence, the required traveled distance by the train will be 18.75 m.