Question

Suppose we toss a coin 4 times. how many different sequences of outcomes are possible if order matters? (for example, hhtt is one outcome and htht is counted as a different outcome)

Answer 1

Solution: Each coin toss has 2 possible outcomes "Head" and "Tail". So if we flip a coin four times, the number of possible outcomes are:

`2^(4) = 16` outcomes.

Let H denotes the Head and T denotes the Tail, then the 16 possible outcomes are enumerated below:

HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT,

THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT