Question

Keep the function x(t)=8∗t−2∗t∗t in the expression evaluator. what is the value of the person’s acceleration a at t=2s?

Answer 1

we are given

position function as

`x(t)=8t-2t^2`

we know that acceleration is second derivative of position

so, firstly, we will find first derivative

`x'(t)=8*1-2*2*t^1`

now, we can simplify it

`x'(t)=8-4t`

now, we can find derivative again

`x''(t)=0-4*1`

`x''(t)=-4`

now, we can plug t=2

and we get

`x''(2)=-4`

so,

the value of the person’s acceleration a at t=2s is -4..........Answer