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1 vote
Rewrite the following as a base-ten numeral: 3(10)^3+5(10)^2+6(10)

2 Answers

5 votes

Answer:

3560

Explanation:

3(10)^3+5(10)^2+6(10)


10^(3) +5×
10^(2)+6×10

We have to solve the above equation


10^(3)= 3×1000=3000


10^(2)=5×100= 500

6×10=60


10^(3) +5×
10^(2)+6×10

=3000+ 500+60

=3560

Hence, the correct answer is 3560

User Mike Corcoran
by
7.5k points
1 vote

3000 + 500 + 60 = 3560

_____

Your calculator can help you out here if you really have no idea that the exponent of 10 tells you the number of zeros: 10^3 = 1000.

User Kucherenkovova
by
8.0k points

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