Question

In an exothermic reaction, chlorine reacts with 2.0200g of hydrogen to form 72.926g of hydrogen chloride gas. how many grams of chlorine reacted with hydrogen

Answer 1

To determine the mass of chlorine that reacted with hydrogen, we can use stoichiometry and set up a proportion to find the unknown mass.

Step-by-step explanation:

In the given reaction, chlorine reacts with 2.0200g of hydrogen to form 72.926g of hydrogen chloride gas.

To determine how many grams of chlorine reacted with hydrogen, we need to calculate the mass of chlorine using stoichiometry.

First, we find the molar mass of hydrogen, which is 2.02 g/mol, and the molar mass of hydrogen chloride gas, which is 36.46 g/mol. Next, we can set up a proportion:

2.0200g H / (2.02 g/mol H) = 72.926g HCl / (36.46 g/mol HCl)

Solving for the unknown, we find that the mass of chlorine is 36.436 g.

Answer 2

Answer : 70.906 grams of chlorine reacted with hydrogen

Explanation :

Step 1 : Write balanced chemical equation.

The balanced chemical equation for the reaction between hydrogen and chlorine gas is given below.

`H_(2) (g) + Cl_(2) (g) \rightarrow 2HCl(g)`

Step 2 : Find moles of H₂ gas.

The moles of H₂ can be found as

`mole = (grams)/(MolarMass)`

We have 2.0200 g of H₂ and molar mass of H₂ is 2.02 g/mol.

Let us plug in these values to find moles of H₂.

`mole =(2.0200g)/(2.02g/mol) = 1 mol`

We have 1 mol of H₂.

Step 3 : Find moles of Cl₂ using mole ratio.

The mole ratio of H₂ and Cl₂ is 1 : 1.

The moles of Cl₂ can be calculated as

`1 mol H_(2) *(1 mol Cl_(2))/(1 mol H_(2)) = 1 mol Cl_(2)`

Step 4 : Find grams of Cl₂.

Molar mass of Cl₂ gas is 70.096 g/mol

Mass of Cl₂ =
`1 mol Cl_(2) *(70.906g)/(mol) = 70.906 g`

We have 70.906 grams of Cl₂