Question

My teacher wanted us to try this out, but I don't understand it as much.

Answer 1

solve for the indicated variable means isolate that variable.

Ans(7)

P=IRT (T)

that means solve for T or make T alone on one side of equal.

To do that we just need to move IR on the left side

So we get:

`(P)/(IR)=T`

Hence final answer will be
`T=(P)/(IR)`

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Ans(8)

2x-3y=8 (y)

-3y=8-2x

`y=(8-2x)/(-3)`

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Ans(9)

V=LWH (L)

`L=(V)/(WH)`

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Ans(10)

A=2(L+W) (w)

A=2L+2W

A-2L=2W

`(A-2L)/(2)=W`

`W=(A-2L)/(2)`

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Ans(11)

ax+by=c (y)

by=c-ax

`y=(c-ax)/(b)`

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Ans(12)

`P=(R-C)/(N)` (R)

PN=R-C

PN+C=R

R=PN+C