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What is the solution to this system of linear equations?

x - 3y = -2
x + 3y = 16


O 1.3
O (3.7)
O2-3)
O (-3,-2)

User Tranbi
by
3.6k points

2 Answers

4 votes

Answer:

(3,7)

Explanation:

x-3y=-2 -----equation i

x+3y=16-----equation ii

Subtract the two equations from each other

-6y=-18

-6y/-6=-18/-6

y=3

Substitute for x in equation i

x-3(3)=-2

x-9=-2

x=-2+9

x=7

x=7,y=3

User Endumiuz
by
4.2k points
4 votes

Answer:

X is 7, and Y is 3.

Explanation:

Step 1: Add 3y to both sides

x - 3y + 3y = -2 + 3y

x = 3y - 2

Step 2: Substitute 3y - 2 for x in x + 3y = 16

x + 3y = 16

3y - 2 + 3y = 16

Step 3: Simplify both sides of equation

6y - 2 = 16

Step 4: Add 2 to both sides

6y - 2 + 2 = 16 + 2

6y = 18

Step 5: Divide both sides by 6

6y/6 = 18/6

y = 3

Step 6: Substitute 3 for y in x - 3y = -2

x - 3(3) = -2

Step 7: Multiply 3 by 3 for 9

x - 9 = 2

Step 8: Switch sides!

x = 9 - 2

Step 9: Subtract 9 minus 2 to get 7

x = 7

With that we have our final answers: x = 7, and y = 3.

User Adriel Werlich
by
4.2k points