Here 'a' corresponds to 0.
Now there are two possibilities for 'r' & 't'
Case 1.
They are on the same side to the right of 'a'
In that case 'r' corresponds to 5 & 't' corresponds to 7.
The midpoint of 'r' and 't' shall be
![(5+7)/(2) =6](https://img.qammunity.org/2019/formulas/mathematics/middle-school/u00dlpavslxxzzjok21104g5da3e2p21kt.png)
Case 2.
Both are on the left of 'a'.
In that case 'r' corresponds to -5 & 't' corresponds to -7
The midpoint shall be
![(-7-5)/(2) =-6](https://img.qammunity.org/2019/formulas/mathematics/middle-school/9epj27ec7x69dtbkaxvr84eq1feerm6l22.png)
Case 3.
'r' in on the right of 'a' and 't' is on the left of 'a'
So 'r' corresponds to 5 and 't' corresponds to -7
The midpoint shall be
![(-7+5)/(2)=-1](https://img.qammunity.org/2019/formulas/mathematics/middle-school/wa84oyzbdj12zy96rvhhvjeftxqrwxliyz.png)
Case 4.
'r' is on the left of 'a' & 't' is on the right of 'a'.
'r' corresponds to -5 & 't' corresponds to 7
The midpoint shall be
![(-5+7)/(2)=1](https://img.qammunity.org/2019/formulas/mathematics/middle-school/viqdn1gblgygzb87vht7dmg8cpsglh6kmj.png)
The possible coordinates of the midpoints of rt are 6, -6, 1, -1.