So, it would be the wisest to work in decimals for this problem.
![image](https://img.qammunity.org/2019/formulas/mathematics/middle-school/yr2jrf55kws9lk1w9hwlktqjomizfbcrn3.png)
So we have to divide 12.125 by 1.8125 to see how many times the latter goes into the former.
![(12.125)/(1.8125)\approx 6.68965517](https://img.qammunity.org/2019/formulas/mathematics/middle-school/qmcrxet9rwntf4uxpwtc2ws0gov2p8wjx3.png)
So, since the problem asks for how many lengths can go in without remainder, our answer would simply be 6.