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What is the sum of the interior angles of a nonagon?

900°

1620°

1440°

1260°

User Renatojf
by
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2 Answers

3 votes

If a polygon has
n sides, the sum of its interior angles is


(n-2)* 180^\circ

A nonagon (from greek "
\varepsilon\\u\\u\varepsilon\alpha", nine and "
\gamma\omega\\u o \\u", angle) has nine sides, so
n=9

If you plug these value into the formula for the sum of inner angles, you have


(n-2)* 180^\circ = (9-2)* 180^\circ = 7* 180^\circ = 1260^\circ

User Sean Cleaver
by
8.0k points
6 votes

Answer:

The answer is 1260 I took the quiz

Explanation:

User The Sasquatch
by
9.1k points

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