Question

Given △DEF, which is not equal to cos(F)? sin(F). sin(D). tan(F). cos(D)

Answer 1

the answer is tan(F)

Answer 2

Answer: The correct option is tan(F).

Step-by-step explanation:

In the given figure the triangle is a right angle triangle because
`\angle E=90^(\circ)`.

It is also given that
`DE=EF=5` and
`DF=5√(2)`.

Since it is an isosceles right angle triangle, therefore the value of perpendicular and base is same for both angles D and F, which is 5.

`\cos (F)=(Base)/(Hypotenuse) =(5)/(5√(2)) =(1)/(√(2))`

The value of cos(F) is
`(1)/(√(2))`.

`\sin (F)=(Perpendicular)/(Hypotenuse) =(5)/(5√(2)) =(1)/(√(2))`

The value of sin(F) is
`(1)/(√(2))`.

`\sin (D)=(Perpendicular)/(Hypotenuse) =(5)/(5√(2)) =(1)/(√(2))`

The value of sin(D) is
`(1)/(√(2))`.

`\tan (F)=(Perpendicular)/(Base)=(5)/(5) =1`

The value of tan(F) is 1. Which is not equal to
`(1)/(√(2))`.

`\cos (D)=(Base)/(Hypotenuse) =(5)/(5√(2)) =(1)/(√(2))`

The value of cos(D) is
`(1)/(√(2))`.

Therefore, the value of tan(F) is not equal to the value of cos(F), so the correct option is third.