To solve this problem, you can use a trick that holds true for every possible triplet of consecutive integers: their sum is always three times the middle number.
In fact, if you call the middle number
, the three consecutive numbers are
and their sum is
![(x-1)+x+(x+1) = x+x+x-1+1 = 3x](https://img.qammunity.org/2019/formulas/mathematics/high-school/v4ga74xrf7b22qgpvzrdp6213a3acxwrdj.png)
So, since
, the middle number is 89. So, the three numbers are 88, 89, 90.