Given, the surface area of a sphere is =
![324\pi cm^2](https://img.qammunity.org/2019/formulas/mathematics/high-school/3r7bd2x4ik8xf1k8glpdxv360zvej8t75n.png)
The formula to find the surface area of a sphere =
![4\pi r^2](https://img.qammunity.org/2019/formulas/mathematics/high-school/6k781bx2877pxrpz8dkbb81dlpbcpvpdk8.png)
Where, r is the radius of the sphere.
As the surface area of the sphere given, we can equate it with the formula.
So we can write the equation as,
![4\pi r^2=324\pi](https://img.qammunity.org/2019/formulas/mathematics/high-school/11tgcazh6zzyifgqvai7gqwtlw85l968vu.png)
To find r, first we have to move 4 to the right side by dividing it to both sides. We will get,
![(4\pi r^2)/4 = (324\pi )/4](https://img.qammunity.org/2019/formulas/mathematics/high-school/uzmnundanuby34eckuez396wtafvx6bwbi.png)
![\pi r^2 = (324\pi )/4](https://img.qammunity.org/2019/formulas/mathematics/high-school/s1ghdwhnt9yod5m3sgarh9uu4dsaoesols.png)
![\pi r^2 = 81\pi](https://img.qammunity.org/2019/formulas/mathematics/high-school/cljlf8swjh66ybabq8psu72wjivtua4evd.png)
Now to find r, we have to move
to the right side, by dividing it to both sides. We will get,
![(\pi r^2)/\pi =(81\pi )/\pi](https://img.qammunity.org/2019/formulas/mathematics/high-school/9zh6sdkdt46kwvc9arzh9hi324idtwzuqv.png)
![r^2 = 81](https://img.qammunity.org/2019/formulas/mathematics/high-school/67n44s2ys3ssvcbqc15o1tf6maone4is9l.png)
Now to find r, we will take square root to both sides.
![√(r^2) = √(81)](https://img.qammunity.org/2019/formulas/mathematics/high-school/k08v1f340xhyhynfswe0ter433yk6is8ak.png)
![r = 9](https://img.qammunity.org/2019/formulas/mathematics/college/sbqlqgr8oyzo7q5it1uyvem2w2t6iimncz.png)
So we have got the radius of the sphere = 9cm.
Now the formula to find the volume of the sphere =
![((4)/(3))\pi r^3](https://img.qammunity.org/2019/formulas/mathematics/high-school/mqcht0ot4uln8vv8c2oyn2hovbuygni35i.png)
Now plugging in the value of r we will get,
Volume =
![(4)/(3) \pi r^3](https://img.qammunity.org/2019/formulas/mathematics/high-school/56o7sdgovz1t5ellvjuydw1bjwbfthd0rl.png)
=
![(4)/(3)\pi (9)^3](https://img.qammunity.org/2019/formulas/mathematics/high-school/s3q2ysohqok111fmxcy8v1phhzlbpo2cpd.png)
=
![(4)/(3)\pi (729)](https://img.qammunity.org/2019/formulas/mathematics/high-school/yhe01kkournpa09a83ih7aruw4qhmiprr2.png)
=
![((4)(729\pi))/(3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/7g1exwbzgld1dp1dbh34xh23khbqf2v0k6.png)
=
![((2916\pi))/(3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/y4lvxb783r38d0huvymu38o3hl0z5g8oy6.png)
=
![(972\pi )](https://img.qammunity.org/2019/formulas/mathematics/high-school/jeapla6at5jnoyuco9lqmqtna3kkbz2j1o.png)
So the required volume of the sphere =
![972\pi cm^3](https://img.qammunity.org/2019/formulas/mathematics/high-school/l7hltevmu36r0097y4x1hefoc0ml4qk7s1.png)