Question

How many moles of solute are present in 1.25 l of a 0.75m nano3 solution?

Answer 1

Hey There!

Volume = 1.25 L

Molarity = 0.75 M

Therefore:

n = M * V

n = 0.75 * 1.25

n = 0.9375 moles

hope this helps!

Answer 2

Step-by-step explanation:

Molarity is defined as the number of moles divided by volume of solution in liter.

Mathematically, Molarity =
`(no. of moles)/(Volume in liter)`

Since, it is given that molarity is 0.75 M and volume is 1.25 liter. Therefore, calculate the number of moles as follows.

Molarity =
`(no. of moles)/(Volume in liter)`

Number of moles =
`Molarity * Volume in liter`

=
`0.75 M * 1.25 l`

= 0.937 mol

Thus, we can conclude that number of moles of solute are present in 1.25 l of a 0.75m nano3 solution is 0.937 mol.