Question

Calculate the mass of silver nitrate (in grams) in a 145 mL solution of 5.88 M AgNO3?

Answer 1

1 mole of AGNO3 weighs 170g
so 0.6322 miles will weigh 170 X 0.6322=107.474 g

Answer 2

Answer: The mass of silver nitrate is 137.5 grams.

Step-by-step explanation:

Molarity is defined as the number of moles present in one liter of solution.

Mathematically,

`\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}`

Or,

`\text{Molarity of the solution}=\frac{\text{Mass of solute}* 1000}{\text{Molar mass of solute}* \text{Volume of solution (in mL)}}`

We are given:

Molarity of solution = 5.88 M

Molar mass of silver nitrate = 170 g/mol

Volume of solution = 145 mL

Mass of silver nitrate = ? g

Putting values in above equation, we get:

`5.58mol/L=\frac{\text{Mass of silver nitrate}* 1000}{170g/mol* 145mL}\\\\\text{Mass of silver nitrate}=(5.58* 170* 145)/(1000)=137.5g`

Hence, the mass of silver nitrate is 137.5 grams.