Alright, lets get started.
Suppose the original deck size: width = x feet
the width is one-fourth the length given in question means length = 4 x feet
Means the originally area =
![x * 4 x = 4 x^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/u66g17nrhzz7ng5kqh29zpqtofcxetie1a.png)
Now the dimensions are changed.
New dimensions, width = (x + 6)
new length = (4x+10)
So, new area will be =
![(x+6) * (4x+10) = 4x^(2) + 10 x + 24 x + 60 = 4x^(2) + 34 x + 60](https://img.qammunity.org/2019/formulas/mathematics/high-school/qixl4kkxtkdjr5h2kn0rtbkvvqox8431z5.png)
the area of the new rectangular deck is 128 ft2 larger than the area of the original deck, means
![4x^(2) + 128= 4x^(2) + 34 x + 60](https://img.qammunity.org/2019/formulas/mathematics/high-school/v6m9e1hvo8roybfylkts79xp3jnrzrx75m.png)
Subtracting
from both sides
![128 = 34 x + 60](https://img.qammunity.org/2019/formulas/mathematics/high-school/6m4vb7zr4hcf365xlpmgflw86qakuj97x0.png)
Subtracting 60 from both sides
![128 - 60 = 34 x + 60 - 60](https://img.qammunity.org/2019/formulas/mathematics/high-school/6sn0zk4sfe21dczexdu4pyxfs56ua89605.png)
![68 = 34 x](https://img.qammunity.org/2019/formulas/mathematics/high-school/ljp2hqvxupla776qc0ejo39jcnoagv51jb.png)
Dividing 34 in both sides
![(68)/(34) = (34 x )/(34)](https://img.qammunity.org/2019/formulas/mathematics/high-school/nnnv7mix5ozbskzzjdypj713my03lyuo13.png)
![x = 2](https://img.qammunity.org/2019/formulas/mathematics/college/v4zl92fn59lvh6ebny7wrqn3v70qes1orj.png)
Means width = 2 feet
Length would be = 4 time width = 4 * 2 = 8 feet
Means dimension of original deck would be = 2 feet and 8 feet :Answer
Hope it will help :)