Question

Find an equation of the line that passes through the points (-0.5,0.75) and (0.75,-0.5)

Answer 1

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Explanation:

Answer 2

The equation of the line can be shown using the slope intercept form that is

y= mx+b

where m is the slope and b is the y intercept

So firstly we have to find the value of slope m

To find the value of slope m we apply the formula

`m= (( y_(2) - y_(1)))/(( x_(2) - x_(1)))`

So we can plug the values using the two given points

(-0.5,0.75) and (0.75,-0.5)

`m= ((-0.5-0.75) )/((0.75-(-0.5))) = (-1.25)/(1.25) = -1`

So m = -1

Plug m=-1 in the equation we get

y= -1x +b

Now we have to find the value of b

to find the value of b , we plug any one pint in the equation

0.75 = -1(-0.5) +b

0.75 = 0.5 +b

Subtract 0.5 from both sides

0.25 = b

or

b= 0.25

Now plug the value of b , in the equation

we get

y = -1x +0.25

hence the equation of the line is y = -1x +0.25