Simplify y to the 1/3 ÷ y to the -3/2 y to the 1/2

Question

asked Jun 26, 2019 105k views

1 Answer

Adam Berman · Answer 1 · 2019-07-02T22:17:46+0000

(y^(1)/(3))/(y^(-3)/(2)y^(1)/(2))

The rule of exponent says , when two terms with same base are in multiplication , the exponents gets added.

for example

a^m * a^ n = a^(m+n)

and when two terms are in division with same base , the exponents are subtracted

for example

a^m /a^n = a^(m-n)

So applying these rules

we get

$\frac{y^(1)/(3)}{y^{(-3)/(2)+(1)/(2)} }$

=
$\frac{y^(1)/(3)}{y^{(-2)/(2)}}$

=
(y^(1)/(3))/(y^(-1))

=
$y^{(1)/(3)-1}$

=
y^(-2)/(3)

=
$\frac{1}{y^{(2)/(3)}}$