Question

Please find the product
(3b+3)(b+7)

Answer 1

(3b+3)(b+7)

Distribute

3b^2+21b+3b+21

=3b^2 +24b +21

Answer 2

Here we have to multiply 3b +3 and b+7 and for that we use distributive property which is (a+b)(c+d)= ac + ad +bc + bd . And on using that rule , we will get

(3b+3)(b+7) =3b(b+7) +3(b+7)

=
`3b^2 +21b +3b+21=3b^2 +24b+21`

And that's the required result .