I'm going to take it from A to B where B is on the horizontal aqua line
A to C is what I think measures 40o. If you go from B horizontally to your right, about 1/2 a unit, you will come to A right above that point. The vertical distance from that new point to A is about 4 units. It's very hard to tell. You could try using a ruler. My ruler gives 4 1/2 cm. Then the horizontal distance is about 0.7 of a cm.
Assuming I'm right, then the Tan of B to A = opposite / adjacent
Tan B = 4.5 / 0.7 = 6.4286
B = tan-1(6.4286)
B = 81.158 degrees.
Again there really is no way to interpret what is meant. A is 55 measured against what? I'm afraid I'm going to have to leave 2 because I have no idea how to reconcile the numbers. Maybe Mathmate or Squaredance knows. I'll leave a note.