Answer:
(7/8)a
Explanation:
Since PQ = QB, PB = 2PQ = AP. Thus P is the midpoint of AB, and Q is the midpoint of PB. Then the midpoint (X) of QB is AP + PQ + QX = 1/2 + 1/4 + 1/8 times the length of AB from A.
The distance from A to the midpoint of QB is (7/8)a.
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