Question

Find the value of cot (theta) for an angle (theta) in standard position with a terminal ray that passes through the point (-9,-5).

a. 5/9

b.5/(sqrt 106)

c. 9/5

d. 9/(sqrt 106)

Answer 1

`P(x,\ y),\ r=√(x^2+y^2)\\\\\cos\theta=(x)/(r)`

`(-9,\ -5)\to x=-9,\ y=-5\\\\r=√((-9)^2+(-5)^2)=√(81+25)=√(106)\\\\\cos\theta=(-9)/(√(106))`