Question

A money box contains only 10 cent and 20 cent coins. There are 34 coins with a total value of $5.40. How many coins of each

Answer 1

let 10 cent coins =x

20 cent coins = y

total number of coins = x+y =34

x=34-y....................(1)

value of coins = $5.40

10x+20y=540

10(34-y) +20y =540

340 - 10y +20y =540

10y=540-340

10y=200

y=20

x=34-y =34-20=14

10 cent coins =x=14 coins

20 cent coins = y = 20 coins