Factor the expression y2+6y-16

Question

asked Aug 24, 2019 98.2k views

2 Answers

AlexeySRG · Answer 1 · 2019-08-25T08:19:04+0000

Step 1 ) Break up the expression.

$\displaystyle\ y^(2) + 6y -16$

$\displaystyle\ (y^(2) -2y) + (8y -16)$

Step 2 ) Factor y from
.

$\displaystyle\ (y^(2) -2y) + (8y -16)$

$\displaystyle\ y ( y - 2 )$

Step 3 ) Factor 8 from

$\displaystyle\ (y^(2) -2y) + (8y -16)$

$\displaystyle\ 8 ( y - 2)$

Step 4 ) Place new factors in group.

$\displaystyle\ y ( y - 2 )$

$\displaystyle\ 8 ( y - 2)$

$\displaystyle\ y(y-2)+8(y-2)$

Step 5 ) Distribute.

$\displaystyle\ y(y-2)+8(y-2)$

$\displaystyle\ (y-2) + 8(y-2)$

$\displaystyle\ (y-2) (y+8)$

The expression factored is...

$\framebox {=(y-2)(y+8)}$

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