Question

Factor the expression y2+6y-16

Answer 1

Step 1 ) Break up the expression.

`\displaystyle\ y^(2) + 6y -16`

`\displaystyle\ (y^(2) -2y) + (8y -16)`

Step 2 ) Factor y from
`y^(2) - 2y`.

`\displaystyle\ (y^(2) -2y) + (8y -16)`

`\displaystyle\ y ( y - 2 )`

Step 3 ) Factor 8 from
`8y - 16`

`\displaystyle\ (y^(2) -2y) + (8y -16)`

`\displaystyle\ 8 ( y - 2)`

Step 4 ) Place new factors in group.

`\displaystyle\ y ( y - 2 )`

`\displaystyle\ 8 ( y - 2)`

`\displaystyle\ y(y-2)+8(y-2)`

Step 5 ) Distribute.

`\displaystyle\ y(y-2)+8(y-2)`

`\displaystyle\ (y-2) + 8(y-2)`

`\displaystyle\ (y-2) (y+8)`

The expression factored is...

`\framebox {=(y-2)(y+8)}`

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- Marlon Nunez

Answer 2

`y^2+6y-16=y^2+8y-2y-16=y(y+8)-2(y+8)=(y+8)(y-2)`