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A sample of argon at 300. °C and 50.0 atm pressure is cooled in the same container to a temperature of 0. °C. What is the new pressure, if the volume and amount of gas do not change?



User Lordofmax
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2 Answers

4 votes
20.6031685 atm for the temperature
User Stephanie Schaye
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2 votes

Answer: 105 atm

Step-by-step explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.


P\propto T (At constant volume and number of moles)


{P_1* T_1}={P_2* T_2}

where,


P_1 = initial pressure of gas = 50 atm


P_2 = final pressure of gas = ?


T_1 = initial temperature of gas =
30^0c=(300+273)K=573K


T_2 = final temperature of gas =
0^0c=(0+273)K=273K


{50* 573}={P_2* 273}


P_2=105atm

Therefore, the new pressure of the gas will be 105 atm.

User Dawid Toton
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