Question

A sample of argon at 300. °C and 50.0 atm pressure is cooled in the same container to a temperature of 0. °C. What is the new pressure, if the volume and amount of gas do not change?

Answer 1

20.6031685 atm for the temperature

Answer 2

Answer: 105 atm

Step-by-step explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

`P\propto T` (At constant volume and number of moles)

`{P_1* T_1}={P_2* T_2}`

where,

`P_1` = initial pressure of gas = 50 atm

`P_2` = final pressure of gas = ?

`T_1` = initial temperature of gas =
`30^0c=(300+273)K=573K`

`T_2` = final temperature of gas =
`0^0c=(0+273)K=273K`

`{50* 573}={P_2* 273}`

`P_2=105atm`

Therefore, the new pressure of the gas will be 105 atm.