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An ideal gas system undergoes an isovolumetric process in which 20J of energy is added as heat to the gas. What is the change in the systems internal energy

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Answer:

the change in the system internal energy is 20 J

Step-by-step explanation:

The computation of the change in the system internal energy is as follows:

Since the volume remains constant so the work done would be zero

Now the change in the internal energy is

= Heat given to system - work done

= 20 J - 0

= 20 J

hence, the change in the system internal energy is 20 J

The same is to be considered

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