Question

Given a mean of 61.2 and a standard deviation of 21.4, what is the z-score of the value 45 rounded to the nearest tenth?0.8−0.90.9−0.8

Answer 1

Answer: It is most likely -0.8

Answer 2

Given: Mean μ = 61.2 and standard deviation σ =21.4

The Z score of the value x=45 is given by

Z =
`(x - mean)/(standard deviation)`

Z =
`(45 - 61.2 )/(21.4)`

Z =
`(-16.2)/(21.4)`

Z = -0.757

The z-score value for 45 rounded to nearest tenth is -0.8