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how many moles of oxygen are in a 7.68L container at 355k and exerting a pressure of 8.57atm on the walls of the container

User Batsheva
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7.8k points

2 Answers

3 votes

We can use the Ideal Gas Law for this question:



PV=nRT


So we need to solve the equation for n, the number of moles:



(PV)/(RT)=n


Now we can plug in the values that we are given to solve for the number of moles:



((8.57atm)(7.68L))/(((0.0821 L *atm)/(mol* K) )(355K))=n



(65.8176)/(29.1455) =n=2.26


So now we know that there are 2.26 moles of oxygen in the container.

User Polpetti
by
8.2k points
4 votes

Step-by-step explanation:

It is given that volume is 7.68 L, temperature is 355 k and pressure is 8.57 atm. So, according to ideal gas equation PV = nRT.

Also, it is known that number of moles equal mass divided by molar mass.

Therefore, putting the given values into the ideal gas equation as follows.

PV = nRT


8.57 atm * 7.68 L =
n * 0.082 atm L/mol K * 355 K

n = 2.26 mol

Thus, we can conclude that the number of moles present in given oxygen is 2.26 mol.

User Coolbeet
by
9.6k points
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