Question

how many moles of oxygen are in a 7.68L container at 355k and exerting a pressure of 8.57atm on the walls of the container

Answer 1

We can use the Ideal Gas Law for this question:

`PV=nRT`

So we need to solve the equation for n, the number of moles:

`(PV)/(RT)=n`

Now we can plug in the values that we are given to solve for the number of moles:

`((8.57atm)(7.68L))/(((0.0821 L *atm)/(mol* K) )(355K))=n`

`(65.8176)/(29.1455) =n=2.26`

So now we know that there are 2.26 moles of oxygen in the container.

Answer 2

Step-by-step explanation:

It is given that volume is 7.68 L, temperature is 355 k and pressure is 8.57 atm. So, according to ideal gas equation PV = nRT.

Also, it is known that number of moles equal mass divided by molar mass.

Therefore, putting the given values into the ideal gas equation as follows.

PV = nRT

`8.57 atm * 7.68 L` =
`n * 0.082 atm L/mol K * 355 K`

n = 2.26 mol

Thus, we can conclude that the number of moles present in given oxygen is 2.26 mol.