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Water runs out of a horizontal drainpipe at the rate of 135 kg/min. It falls 3.1 m to the ground. Assuming the water doesn't splash up, what average force does the water exert on the ground

User Jae Carr
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1 Answer

11 votes

Answer:

The average force exerted by the water on the ground is 17.53 N.

Step-by-step explanation:

Given;

mass flow rate of the water, m' = 135 kg/min

height of fall of the water, h = 3.1 m

the time taken for the water to fall to the ground;


h = ut + (1)/(2)gt^2\\\\h = 0 + (1)/(2)gt^2\\\\t = \sqrt{(2* 3.1)/(9.8) } \\\\t = 0.795 \ s

mass of the water;


m = m't\\\\m = 135 \ (kg)/(min) \ * \ 0.795 \ s \ * \ (1 \ \min)/(60 \ s) \ = 1.789 \ kg

the average force exerted by the water on the ground;

F = mg

F = 1.789 x 9.8

F = 17.53 N

Therefore, the average force exerted by the water on the ground is 17.53 N.

User Adi Tiwari
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