123k views
5 votes
What’s the equation of the line that passes through (-4,3) and is perpendicular to the line y=7/5x-3/5

A) 5x+7y=1
B) 7x+5y=-13
C) 7x+5y=-1
D) 3x+5y=7

1 Answer

5 votes

Two lines perpendicular to each other having slopes m1 and m2 are related as:

m1 * m2=-1 ...................... (1)

First we find slope m1 of the line y=7/5x-3/5

comparing this equation with slope intercept form y=mx+b,

slope m1=7/5

NOw using rule (1) here to get value of m2

7/5 * m2 =-1

m2 =-5/7...................(2)

Now the line passes through (-4,3) and has slope m2 =-5/7

we use slope intercept form to get the value of y intercept

y=mx+b

3=(-5/7)(-4) +b

3=2.86 +b

b=0.14

At last we plug the value of b and m in slope intercept form to get the final equation as :

y=(-5/7) x + 0.14

User Nagabhushan Baddi
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories