Answer and explanation :
Given :
To find :
I. Use the zero product property to set up two equations that will lead to solutions to the original equation.
Solution :
The zero product property state that,
If
then x=0 or y=0 (or both x=0 and y=0)
Applying zero product property we get,


The two equations form is
....(1)
......(2)
II. Use a reciprocal identity to express the equation involving secant in terms of sine, cosine, or tangent.
Solution :
The reciprocal identity is flipping of a number,
The reciprocal of secant is 1 by cosine

Substitute in the given equation,

III. Solve each of the two equations in Part I for x, giving all solutions to the equation
Solution :
The two equations form is
....(1)
......(2)
Solving equation (1)





Solving equation (2)




Therefore, The solutions of the equation is
