Answer and explanation :
Given :
To find :
I. Use the zero product property to set up two equations that will lead to solutions to the original equation.
Solution :
The zero product property state that,
If
then x=0 or y=0 (or both x=0 and y=0)
Applying zero product property we get,
![(\cos x-(√(2))/(2))(\sec x-1)=0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/powth26nmx2q9iqowbfstm90mt1h3ugrzk.png)
![(\cos x-(√(2))/(2))=0\text{ or }(\sec x-1)=0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zw0ghig1upq1wez6gtu9ve82r4akk7lks2.png)
The two equations form is
....(1)
......(2)
II. Use a reciprocal identity to express the equation involving secant in terms of sine, cosine, or tangent.
Solution :
The reciprocal identity is flipping of a number,
The reciprocal of secant is 1 by cosine
![sec x=(1)/(cos x)](https://img.qammunity.org/2019/formulas/mathematics/college/83uzafrbtcetmblqu3odith9wp5fks144w.png)
Substitute in the given equation,
![(\cos x-(√(2))/(2))((1)/(cos x)-1)=0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/dhb4q361ete9e33xhg5kdxl5o3jafp82u2.png)
III. Solve each of the two equations in Part I for x, giving all solutions to the equation
Solution :
The two equations form is
....(1)
......(2)
Solving equation (1)
![\cos x-(√(2))/(2)=0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/7k3wxe27hcxzeee2tsts3c7tk1hnoknhhq.png)
![\cos x-{1}\frac{√(2)}=0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/x4uwglng6aeg3nbi6d222y2jr8679qtls1.png)
![\cos x={1}\frac{√(2)}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/56djsm988gycuzlb74o9zcstxc1nge2co5.png)
![\cos x=\cos (\pi)/(4)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/66otbg8tir5418ruuyxmwwrkm45piof41g.png)
![x=(\pi)/(4)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/4pnn85duj9dgsz6u6e0jcn4fj2ws5sjbi9.png)
Solving equation (2)
![\sec x-1=0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/7lspof82di2jqrjnfz5uh8mu7pjb8ew3d0.png)
![\sec x=1](https://img.qammunity.org/2019/formulas/mathematics/middle-school/kxbk809k67u083zfisx3qy03e3gtgbiann.png)
![\sec x=\sec 0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/7y3sv15afmxda9ijo3lhqgwq5ny3uw5q2j.png)
![x=0](https://img.qammunity.org/2019/formulas/mathematics/high-school/9kvijf358dstmx6gyc4kvxfk183uebfiu1.png)
Therefore, The solutions of the equation is
![x=0,(\pi)/(4)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/8n5oxzll84vxdx4s8e3bzrk1w3ul155p4a.png)