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Sin(theta/2)=1/2

I. Write an equation that expresses the value of (theta/2)  in terms of an appropriate inverse trigonometric expression. 

II. On the interval [0, 2pi], what values of (theta/2) satisfy your equation in Part I? 

III. On the interval [0, 2pi], what values of theta does your answer to Part II produce?

IV. Write an expression for all solutions to the equation.

1 Answer

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Part I: sin (theta/2) = 1/2 So, theta/2 = sin inv(1/2) Part II: On the interval [0,2pi], theta/2 = 30 degrees i.e. pi/6 degrees or 150 degrees i.e. 5pi/6...


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