Hi there!
![(f +g )(x) = f(x) +g (x)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/j7pf474ezie0t39yaetie4jj3i6mrrb8ix.png)
In other words: to find (f + g)(x) we must add up the functions f(x) and g(x). Substitute both functions into the formula.
![(f + g)(x) =( 4x {}^(2) + 1) + ( {x}^(2) - 5)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/1nsilk6xmr4xt791avcnfznbto84rbc5bv.png)
Remove the parenthesis, since they don't have a function in this situation.
![(f + g)(x) =4x {}^(2) + 1 + {x}^(2) - 5](https://img.qammunity.org/2019/formulas/mathematics/middle-school/15v6i3jvpadf14tng5j5ogh1x46720764i.png)
Rearrange the expression in order to collect terms later.
![(f + g)(x) = 4x {}^(2) + {x}^(2) + 1 - 5](https://img.qammunity.org/2019/formulas/mathematics/middle-school/p6jz5if1lvgrm1v59jbhlfahd6up10hvh8.png)
And finally collect the terms.
![(f + g)(x) = 5x {}^(2) - 4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/jbowp74nt8sxwzbdkiq2a6cpgsyvs52fs3.png)
~ Hope this helps you!