Question

An object accelerates from rest with a constant acceleration of 8.4 m/s^2. How fast will it be traveling after it goes 39 m? *

Answer 1

S distance/displacement = 39
U initial velocity = 0
V final velocity = ?
A acceleration = 8.4
T time = unneeded

v(squared) = u(squared) + 2as
x(squared) = 0(squared) + (2 x 8.4 x 39)
x(squared) = 655.2
x = square root of 655.2 = 25.597

Final velocity (answer) = 25.597m/s