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What is the arc length if theta = 6pi over 5 and the radius is 2cm
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What is the arc length if theta = 6pi over 5 and the radius is 2cm

User Aton
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\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ ------\\ r=2\\ \theta =(6\pi )/(5) \end{cases}\implies s=2\cdot \cfrac{6\pi }{5}\implies s=\cfrac{12\pi }{5}
User Marine
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