Graph x^2-6x-y^2+4y-4=0

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asked Nov 28, 2019 45.1k views

2 Answers

Thomas Dondorf · Answer 1 · 2019-12-01T10:24:30+0000

Actually, this is supposed to be a graph of a circle. So, the equation would be (x-3)^2-(y-2)^2=9 Thus, your center would be at (3,2) with a radius of 3. Lmk if you have any questions :))

Graph x^2-6x-y^2+4y-4=0

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