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Graph x^2-6x-y^2+4y-4=0

Graph x^2-6x-y^2+4y-4=0
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1 vote
Graph x^2-6x-y^2+4y-4=0

User Bogi
by
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2 Answers

6 votes
Actually, this is supposed to be a graph of a circle. So, the equation would be (x-3)^2-(y-2)^2=9 Thus, your center would be at (3,2) with a radius of 3. Lmk if you have any questions :))
User Thomas Dondorf
by
8.1k points
5 votes
Hopefully this helps.
Go to desmos.com and enter your equation to see.
Graph x^2-6x-y^2+4y-4=0-example-1
User Adeline
by
8.9k points
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