Question

Indicate the type of hybrid orbitals used by the central atom in tef4

Answer 1

`sp^3d`

Step-by-step explanation:

Hello,

The type of hybrid orbitals used by the tellurium could be found via the following formula:

`hybridisation=(1)/(2)(\# valence.elec+Monovalent.bonds)`

In this case, tellurium has six valance electrons and four monovalent bonds (those four fluorines), thus:

`hybridisation=(1)/(2) (6+4)=5`

Such result, indicates a
`sp^3d` hybridisation which accounts for one ‘s’, three ‘p’ and one ‘d’ orbitals of almost equal energy which give five identical and degenerated hybrid orbitals arranged in trigonal bipyramidal symmetry.

Best regards.

Answer 2

Answer : s
`p^(3)`d

Explanation : While we are considering the molecule of Te
`F_(4)` it forms trigonal bi-pyramidal structure which undergoes s
`p^(3)`d hybridisation. The lone pair of Te takes the equatorial position in the molecular structure.