Question

Find the general indefinite integral. (9-t) (4+t^2) dt

Answer 1

Best thing to do with this is to FOIL it out to a third degree polynomial then integrate it term by term. In standard form the polynomial is
`\int\limits {(36-4t+9t^2-t^3}) \, dt`. We will use C as our constant of integration. The integral now, assuming you know the rules for exponents, is
`36t- (4t^2)/(2)+ (9t^3)/(3)- (t^4)/(4)+C`. Simplifying that we would get
`36t-2t^2+3t^3- (1)/(4)t^4+C`. There you go!