Answer: C) 12.40
Step-by-step explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.
![pH=-\log [H^+]](https://img.qammunity.org/2019/formulas/physics/high-school/iidawris7irvi0bu33z0a9xjzagtaknk6o.png)
![pOH=-log{OH^-}](https://img.qammunity.org/2019/formulas/physics/high-school/3sm788siiqw45jh20qetr7rmxlf3t6ujom.png)
![pH+pOH=14](https://img.qammunity.org/2019/formulas/physics/high-school/otjd6ndbvk7y7ydxz3hi0tqp69ayf7y56e.png)
Given:
![[H^+]=0.025 M](https://img.qammunity.org/2019/formulas/chemistry/high-school/nuu3dw8d4rubiknjf84u8d8toue9ze4sjp.png)
![pH=-log[0.025]](https://img.qammunity.org/2019/formulas/chemistry/high-school/cynijvcttfpgy0v3w0wr3et23jgzm60tra.png)
![pH=1.6](https://img.qammunity.org/2019/formulas/chemistry/high-school/zvdbu57qkl7wq6ew3znwguy3z2zkjwgigb.png)
![1.6+pOH=14](https://img.qammunity.org/2019/formulas/chemistry/high-school/5d14ryiefdjgcnxg4akq1pyun28oydwx7x.png)
![pOH=12.40](https://img.qammunity.org/2019/formulas/chemistry/high-school/wm2qen5a1xgqledswkp992h8dvt60jkyf7.png)
Thus pOH of the solution is 12.40