Question

Solve the equation by completing the square. 2x-18x+58=0

Answer 1

jorgepollo avatar

o sorry

jorgepollo avatar

the x^2-18x+58=0

KONSETON avatar

right now it's square :)

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Explanation:

Answer 2

`x^(2) -18x+58=0`

We have got quadratic equation. We calculate it by using Δ.


`\Delta=(-18)^(2) -4*1*58=324-232=92>0`

`√(\Delta) = √(92) =2 √(23)`


`x_1= (-b- √(\Delta) )/(2a) = (18-2 √(23) )/(2) =9- √(23)`
∨

`x_2= (-b+ √(\Delta) )/(2a) = (18+2 √(23) )/(2) =9+ √(23)`

Hope it helps :)