The correct answer is option #1. x = -2 +/- 2i
We can find this by using the quadratic equation, which is written below.
![\frac{-b +/- \sqrt{ b^(2) -4ac} }{2a}](https://img.qammunity.org/2019/formulas/mathematics/college/z71j7ab1ey7zhk1r4dd4bwm1dnfn1cfypr.png)
Now we know the a, b and c values by looking at the equation. a is always the number attached to x^2 (which is 1), b is always the number attached to x (which is 4) and c is the number with no variable (which is 8). So we can place them in in the appropriate spots in the equation.
![\frac{-b +/- \sqrt{ b^(2) -4ac} }{2a}](https://img.qammunity.org/2019/formulas/mathematics/college/z71j7ab1ey7zhk1r4dd4bwm1dnfn1cfypr.png)
![\frac{-4 +/- \sqrt{ 4^(2) -4(1)(8)} }{2(1)}](https://img.qammunity.org/2019/formulas/mathematics/college/ez4hnja2v58h4wbsvbe4kmc6lfn9mm96st.png)
![(-4 +/- √( 16 - 32) )/(2)](https://img.qammunity.org/2019/formulas/mathematics/college/aec5jus2uxmbn4qslwbyry5v6c64smj3hf.png)
![(-4 +/- √( -16) )/(2)](https://img.qammunity.org/2019/formulas/mathematics/college/itzszb6r48bu7s2m25xdj46he0yc5gzc13.png)
![(-4 +/- 4i )/(2)](https://img.qammunity.org/2019/formulas/mathematics/college/qw67zbax8lkuf5xcpacvmvb23ihxfksbzi.png)
-2 +/- 2i