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Write the sum using summation notation assuming the suggested pattern continues. -8-3+2+7+...+67

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You can use the generic representation of a term of an arithmetic sequence:

a_n=a_1+d(n-1)
Filling in the values a₁=-8, d=5, you have

a_n=-8+5(n-1)\\a_n=-13+5n

Then the value of n for the last term can be found as
67 = -13 + 5n
80 = 5n
16 = n
and the sum can be written as


S_(16)=\sum\limits_(n=1)^(16){(-13+5n)}
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