Given;
Probability of machine A breaking down, P(A) = 2% = 0.02
And, probability of machine B breaking down, P(B) = 2.5% = 0.025
Then, the probability that machines A and B will break down on the same day is;
P(A&B) = P(A)P(B) = P(A)*P(B) = 0.02*0.025 = 0.0005
In percentage form;
P(A&B) = 0.0005*100 = 0.05%