Answer:
![m_(Si)=5.04gSi](https://img.qammunity.org/2019/formulas/chemistry/middle-school/34suby9q0dasoyxjs7q5iha6tco6ewf2q5.png)
Step-by-step explanation:
Hello,
In this case, we use the Avogadro's number and the atomic mass of silicon to find the grams that are present in that amount of atoms by using the following atoms-mole-mass relationship:
![m_(Si)=1.08x10^(23)atomsSi*(1molSi)/(6.022x10^(23)atomsSi) *(28.1gSi)/(1molSi) \\\\m_(Si)=5.04gSi](https://img.qammunity.org/2019/formulas/chemistry/middle-school/3ywdbluykc00a3p56pzqil6kd81c73fuom.png)
That is why in mole of silicon there are 6.022x10^(23) atoms of silicon as well as 28.1 g of silicon.
Best regards.